Etext 8.46

8.46-A random sample of 10 miniature tootsie rolls was taken from a bag. Each piece was weighed on a precise use up scale. The results in grams were: 3.087, 3.131, 3.241, 3.270, 3.353, 3.400, 3.411, 3.437, 3.477 (a) Construct a 90% sanction time interval for the true mean weight. Sample mean = 3.3048 Sample timeworn deviation = 0.13199 Standard error: 1.645*0.13199/Sqrt(10) = 0.06866 90% CI- 3.3048-0.06866 < u < 3.3048 + 0.06866 90% CI- 3.23614 < u < 3.37346 (b) What sample size would be necessary to work out the true weight with an error rate of +/- 0.03 grams with 90% sanction? n = [1.645*0.13199/0.03]^2 = 7.42^2 = 52.38 Rounding up to heyday for n = 53 (c) Discuss the factors which might cause innovation in the weight of the tootsie rolls during manufacturing. Factors such as the amount of ingredients utilize to pick out the tootsie rolls along with the humidity and temperature control. Also the gondola tolerances may be a factor in creat e variation during manufacturing. 8.

62- In 1992, the FAA conducted 86,991 pre-employment drug tests on the job applicants who were to be engaged in safety and security related jobs, and ready that 1,143 were absolute. (a) Construct a 95% confidence interval for the universe proportion of positive drug tests. p-hat = 1143/86991 = 0.013139... E = 1.96*sqrt[(0.013139)*(0.98686)/86991] = 0.002393 CI is (0.013139 0.002393, 0.013139 + 0.00239) (b) wherefore is the normality speculation not a line of work, disrespect the very small care for of p? The normality assumption was not a problem because the random sample was very lar ge.If you want to get a full essay, order it! on our website: BestEssayCheap.com

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